Aleksandra Goryachkina, left, has defeated Bulgaria's Nurgyul Salimova ©FIDE/Stev Bonhage

Aleksandra Goryachkina has won the International Chess Federation (FIDE) Women's World Cup here, defeating Bulgaria's Nurgyul Salimova with a score of 1.5-0.5 in the tiebreaks.

Russian Goryachkina, playing as a neutral, had been a runner up in 2021.

The decisive moment came in game two of the tie break and Salimova resigned after move 105 to give Goryachkina the title.

It carried with it a first prize of $50,000 ($39,200/€45,865). 

Both players had already clinched a place in the FIDE Candidates' Tournament for the Women's World Championship next year.

Meanwhile, India’s Rameshbabu Praggnanandhaa defeated Fabiano Caruana of the United States 3.5-2.5 in a tie break to make sure of his place in the FIDE Open World Cup final where he will meet world number one Magnus Carlsen of Norway.

"I didn't expect to play Magnus in this tournament at all because the only way I could play him was in the final, and I didn't expect to be in the final, I will just try to give my best and see how it goes," Praggnanandhaa said.

At 18, Praggnanandhaa is the third youngest after the American Bobby Fischer and Carlsen to qualify for a Candidates Tournament.

Game one of the FIDE Open World Cup final is set to begin tomorrow.